Example-01: What will be the momentum of a stone having mass of 10 kg when it is thrown with a velocity of 2 m/s?

Solution: Given, Mass (m) = 10 kg

Velocity (v) = 2 m/s

Momentum (p) = ?

We know that, Momentum (p) = Mass (m) x Velocity (v)

Therefore, p=10 kg × 2 m/s = 20 kgm/s

Thus the momentum of the stone = 20 kgm/s

 

Example-02: Calculate the momentum of a bullet of 25 g when it is fired from a gum with a velocity of 100 m/s.

Solution: Given, Velocity of the bullet (v) = 100 m/s

Mass of the bullet (m) = 25 g = 25/1000 kg = 0.025 kg

Momentum (p) = ?

or, p = 2.5 kgm/s

Thus the momentum of the bullet = 2.5 kgm/s

 

Example-03: Calculate the momentum of a bullet having mass of 25 g is thrown using hand with a velocity of 0.1 m/s.

Solution: Given, Velocity of the bullet (v) = 0.1m/s

Mass of the bullet (m) = 25 g = 25/1000 kg = 0.025 kg

Momentum (p) = ?

We know that, Momentum (p) = Mass (m) x Velocity (v)

Therefore, p=0.025 kg × 0.1m/s

or, p=0.0025 kgm/s. Thus the momentum of the bullet = 0.0025 kg m/s

 

Example-04: The mass of a goods lorry is 4000 kg and the mass of goods loaded on it is 20000 kg. If the lorry is moving with a velocity of 2 m/s what will be its momentum ?

Solution: Given, Velocity (v) = 2 m/s

Mass of lorry = 4000 kg, Mass of goods on the lorry = 20000 kg

Therefore, total mass (m) of the lorry = 4000 kg + 20000 kg = 24000 kg

Momentum (p) = ?

We know that, Momentum (p) = Mass (m) x Velocity (v)

Therefore, p = 24000 kg×2 m/s = 48000 kgm/s

Thus, momentum of the lorry = 48000 kgm/s

 

Example-05: A car having mass of 1000 kg is moving with a velocity of 0.5 m/s. What will be its momentum?

Solution: Given, Velocity of the bullet (v) = 0.5 m/s

Mass of the bullet (m) = 1000 kg

Momentum (p) = ?

We know that, Momentum (p) = Mass (m) x Velocity (v)

Therefore, p = 1000 kg × 0.5 m/s

or, p = 500 kgm/s. Thus the momentum of the bullet = 500 kgm/s

 

Example-06: A vehicle is running with a velocity of 5 m/s. If the momentum of the vehicle is 5000 kgm/s, what is its mass?

Solution: Given, Momentum (p) = 5000 kgm/s

Velocity (v) = 5 m/s

Mass (m) = ?

We know that, Momentum (p) = Mass (m) x Velocity (v)

Therefore, 5000 kgm/s = m × 5 m/s

⇒ m = 5000 kgms^-1 / 5 ms^-1 = 1000 kg

Thus, mass of the vehicle = 1000 kg

 

Example-07: A stone attains a momentum of 1 kg m/s when it flies with a velocity of 2 m/s, then what will be mass of the stone?

Solution: Given, Momentum (p) = 1 kg m/s

Velocity (v) = 2 m/s

Mass (m) = ?

We know that, Momentum (p) = Mass (m) x Velocity (v)

Therefore, 1 kgm/s = m × 2 m/s

⇒ m = 1 kgms^-1/ 2 ms^-1 = 0.5 kg = 500 g

Thus, mass of the stone = 0.5 kg or 500 g

 

Example-08: When a bullet is fired from a rifle its momentum become 20 kgm/s. If the velocity of the bullet is 1000 m/s what will be its mass?

Solution: Given, Momentum (p) = 20 kgm/s

Velocity (v) = 1000 m/s

Mass (m) = ?

We know that, Momentum (p) = Mass (m) x Velocity (v)

Therefore, 20 kgm/s = m × 1000 m/s

⇒ m = 20 kgms^-1 /1000 ms^-1 = 150 kg = 0.02 kg = 20 g

Thus, mass of the bullet = 20 g

 

Example-09: When a missile is fired from a tank it gets a momentum of 2000 kg m/s. If the velocity of the missile is 50 m/s what will be its mass?

Solution: Given, Momentum (p) = 2000 kgm/s

Velocity (v) = 50 m/s

Mass (m) = ?

We know that, Momentum (p) = Mass (m) x Velocity (v)

Therefore, 2000 kgms^-1 = m × 50 ms^-1

⇒ m = 2000 kgms^-1 /50 ms^-1 = 40 kg

Thus, mass of the missile = 40 kg

 

Example-10: A bird is flying with a velocity of 3 m/s. If the momentum of the bird is 3.60 kgm/s what is its mass ?

Solution: Given, Momentum (p) = 3.60 kgm/s

Velocity (v) = 3 m/s

Mass (m) = ?

We know that, Momentum (p) = Mass (m) x Velocity (v)

Therefore, 3.60 kgm/s = m × 3 ms^-1

⇒ m = 3.60 kg ms^-1/ 3 ms^-1 = 1.2 kg =1 kg 200 g

Thus, mass of the bird = 1 kg 200 g

 

Example-11: If the momentum of a flying brick is 50 kgm/s and its mass is 10 kg. Calculate its velocity?

Solution: Given, Momentum (m) = 50 kgm/s

Mass (m) = 10 kg

Velocity (v) = ?

We know that,

Momentum (p) = Mass (m) x Velocity (v)

⇒ 50 kg m/s = 10kg × v

⇒ v = 50 kgms^-1/10 kg= 5 ms^-1

Thus, velocity of the brick = 5 ms^-1

 

Example-12: A bullet of 25 g is when fired from a piston gets a momentum of 50 kgm/s. Calculate the velocity of bullet.

Solution:

Given, Momentum (m) = 50 kgm/s

Mass (m) = 25 g = 25/1000 kg = 0.025 kg

Velocity (v) = ?

We know that,

Momentum (p) = Mass (m) x Velocity (v)

⇒ 50 kg m/s = 0.025 kg × v

⇒ v = 50 kgms^-1/0.025 kg = 2000 ms^-1

Thus, velocity of the bullet = 2000 ms^-1

 

Example-13: A vulture when flying with a velocity ‘v’ attains a momentum of 20 kg m/s. If the mass of the vulture is 25 kg what is the value of ‘v’?

Solution:

Given, Momentum (m) = 20 kgm/s

Mass (m) = 25 kg

Velocity (v) = ?

We know that, Momentum (p) = Mass (m) x Velocity (v)

⇒ 20 kg m/s = 25 kg × v

⇒ v = 20 kgms^-1 /25 kg = 0.8 ms^-1

Thus, velocity of the vulture = 8 ms^-1

 

Example-14: A brick after falling from a hill collide with ground with a momentum of 100 kgm/s. If the mass of the brick is 5 kg what was its velocity while colliding with the ground?

Solution:

Given, Momentum (m) = 100 kgm/s

Mass (m) = 5 kg

Velocity (v) = ?

We know that,

Momentum (p) = Mass (m) x Velocity (v)

⇒ 100 kgm/s = 5 kg × v

⇒ v = 100 kgms^-1 /5 kg = 20 m/s

Thus, velocity of the brick = 20 m/s

 

Example-15: Calculate the velocity of a missile having mass of 100 kg, if it attains a momentum of 5000 kgm/s when fired from a rocket gun?

Solution:

Given, Momentum (m) = 5000 kgm/s

Mass (m) = 100 kg

Velocity (v) = ?

We know that, Momentum (p) = Mass (m) x Velocity (v)

⇒ 5000 kg m/s = 100 kg × v

⇒ v = 5000 kg ms^-1 /100 kg = 50 m/s

Thus, velocity of the missile = 50 m/s